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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 ! N$ I5 [1 x2 v g, u% N7 X f
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足球看完了来看看题目。- V% s& N( r# U/ X& Q* u
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)$ m7 X: B3 g4 g* z) D
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
$ R; x# X! u& Y5 P, w2 ], xWe can see it is not easy to install the 22 meters heat trace according as figure 1) t* i! n* i" o, {5 Z7 K$ }
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( H$ F! _0 T9 Z& _% x7 G ~As a normal question we just discuss:6 d5 C# q$ U0 P' I- A
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 1 M* L$ ~' l+ G
I call this is JACK LAI Spiral Method 螺旋法
1 v L& h. t4 L. rThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.2 J, A& k( d" R, h1 k. U
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
& ~ A# ]; V6 ?% [ H w. g( ?3 ?( aBecause the pipe is horizontal, position 0 can not be placed. See figure 2
5 U, t5 N# c) L. k* y& I! dBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
1 J$ P5 U7 K; v5 ]6 F. x5 X; X4 eThe total heat trace that can be installed here is about & C( o4 Y8 e5 X/ c+ \& s
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
5 R. r7 ^0 Q2 I/ x1 ASo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. ' z% y' S0 G' ?# O
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Note :0 {4 f* ~- d0 s* T. X: F. B2 S$ P
1. The minimum bend radius:. ?+ `; ]5 D! q( w- a
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
) R8 u( o6 L+ U* V( Y0 t+ U5/16 *6 = 30/16 almost = 2 inches
% X9 Q: Y7 g6 p) i5 [So the maximum bend radius is 2 inches.$ I# o" k3 |& R6 e. P
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As regular
+ D, B8 h/ J0 o0 o/ O' HFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe/ q% \- ^+ x$ d. h2 e
if the pipe is horizontal, The length of heat trace can be installed is about
2 o. w, |( c3 }: X: N1 * 9 = 9 meters
' J/ y: N/ _ pIf the pipe is vertical, The length of heat trace can be installed is about& k0 w9 V( A* @, M+ v- K, X% I
1 * 10 = 10 meters. / m7 ^- I4 j& b( v, a
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe' W& G1 y7 l/ @% x9 b
if the pipe is horizontal , The length of heat trace can be installed is about- x& A+ _& V! D0 L
1 * 4 = 4 meters
; {9 U. |1 ?7 |8 v/ YIf the pipe is vertical, The length of heat trace can be installed is about
2 S' U, k2 a1 @$ j4 L2 T g, B3 Y1 * 5 = 5 meters. |
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