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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 9 ?4 I7 f( m% Z! H
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足球看完了来看看题目。: Y0 h, l. _7 H1 x
" ?; h7 h- t ~. }' k, {The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)( I1 Z& [" [; _4 t& M9 V6 g2 _8 q
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
O5 ]% ?3 k; {We can see it is not easy to install the 22 meters heat trace according as figure 1! C* s' d" ~- [
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* |! L1 }4 @2 |7 }As a normal question we just discuss:) j7 B/ H' ] I1 R5 r
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? * B/ @' K* _- D/ a8 u4 y
I call this is JACK LAI Spiral Method 螺旋法1 H8 x8 w+ S4 Z
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
- t: M1 n) |1 q8 S5 I% p0 pThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. & E; q5 Y; e5 F( N% [! G. ^4 T
Because the pipe is horizontal, position 0 can not be placed. See figure 2
. e m( i( i9 {7 `Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 36 A f9 J- c3 f) N# I$ k! P( n
The total heat trace that can be installed here is about
# B1 h0 N) i* q- W1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
; I5 s9 x2 D' S- J0 |6 n! c/ f: bSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. % F: q9 I% {: t6 L
" _5 j2 O$ N" h$ I8 zNote :9 k$ `9 r' u u4 @
1. The minimum bend radius:
7 c: A0 u! O1 MBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is5 X# S0 n) l+ d' N7 g" w0 J
5/16 *6 = 30/16 almost = 2 inches+ ]2 B: @5 s' C
So the maximum bend radius is 2 inches.0 y# A- x) ~1 w/ N
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As regular 4 K) @! T* ?4 M. C* f, E$ c
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe7 ~6 ]' m! \, t/ h
if the pipe is horizontal, The length of heat trace can be installed is about, g( V6 L' R( i+ }6 B$ ]
1 * 9 = 9 meters
) u F4 l6 y2 o! L- M/ jIf the pipe is vertical, The length of heat trace can be installed is about7 u' X2 p, Z( n. L z& v3 ^
1 * 10 = 10 meters.
2 }: o2 E7 e: @9 S$ [For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
2 X9 F! L# ~" K2 qif the pipe is horizontal , The length of heat trace can be installed is about% g; d% C% ]; @/ L- j
1 * 4 = 4 meters) q, e8 {/ M9 o |' X$ ~# j* Z
If the pipe is vertical, The length of heat trace can be installed is about8 E ?# J% D" L
1 * 5 = 5 meters. |
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