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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置9 {) n7 I& r8 U2 l0 Z
" Q6 G! @) B# y( O, j) v/ I
* c& w+ ^$ c8 ^8 H* O7 U+ F f* R; X5 M4 ^7 d& u/ L
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:% a h) p$ I; g+ K
( b; j* ?0 Y( y7 O; Z) Wmz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.
% h9 C& v' ?$ l; v+ @. h) y" c1 K" v, B- B, B
Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).& M) P0 V |/ D J- C+ n( k
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发表于 2012-4-2 21:27
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