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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 ; O$ L" m2 R- F7 z0 s# k
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1# jack_lai
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足球看完了来看看题目。0 _: K$ f& B$ i
+ {1 b* Y. T8 e) X( w( pThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
% D" d* x& ]+ w* y1 z% y2 pThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
: O- t( q! e5 S. |We can see it is not easy to install the 22 meters heat trace according as figure 1
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As a normal question we just discuss:
s3 i8 e- O C- S( t. ?How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? ( g) t1 p* \6 n1 w- y8 F, F& q
I call this is JACK LAI Spiral Method 螺旋法0 z2 a# V g: U+ k3 r: f: p
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
' C5 I2 \' p% P" U0 `( W* [2 e) P$ bThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
* m7 |1 Z O0 _7 Q4 ]# ?2 ZBecause the pipe is horizontal, position 0 can not be placed. See figure 21 o' j. R6 Y6 p! B6 r
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3- E. d) \8 U0 E7 J) C8 @/ C
The total heat trace that can be installed here is about ' s3 }+ R( W1 f/ ~+ N
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters; M# t1 A; q6 _; }9 {. k5 G
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 3 z, n3 d: a. ?! Q
8 x. s6 q p( d2 L! PNote :; J2 K! I: o a0 ?
1. The minimum bend radius:- U: W h* x4 R8 t- Q, R5 M/ v
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is6 y7 D7 [ p& g
5/16 *6 = 30/16 almost = 2 inches
+ a# J( J6 m7 mSo the maximum bend radius is 2 inches./ d4 r; j: l8 T6 ?3 Y3 w8 |
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Summary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
4 J) g2 v- Y+ p, C4 Y Aif the pipe is horizontal, The length of heat trace can be installed is about
4 W% i. I* f7 N$ O& @! H' B2 ?( E1 * 9 = 9 meters
/ q5 k8 Y- N5 BIf the pipe is vertical, The length of heat trace can be installed is about5 W( D2 B4 M* j1 U+ P
1 * 10 = 10 meters.
6 v7 A8 R2 h. P- BFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
8 V$ [! R* q1 d5 Sif the pipe is horizontal , The length of heat trace can be installed is about1 H8 D4 F `/ m) ?: {
1 * 4 = 4 meters2 T& B3 w2 u2 C1 U- A% `( n, w+ |
If the pipe is vertical, The length of heat trace can be installed is about
: C# \. a* Q4 q& v1 * 5 = 5 meters. |
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