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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 2 |3 ?0 }1 k& b6 q
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1# jack_lai * }$ M' y! B% Z
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足球看完了来看看题目。/ J" Y: v$ _; `
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)- g1 y0 Q8 a' Y; `0 H+ f" g9 u
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
* C0 A9 S' q$ ^& p* _* J( sWe can see it is not easy to install the 22 meters heat trace according as figure 1( |% ^: p" j* \' q
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As a normal question we just discuss:! [" V% O& w7 J9 l
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 9 I9 \6 u" C% n& b5 c! l$ m
I call this is JACK LAI Spiral Method 螺旋法9 b$ X$ O; \4 g' a
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.: g7 L) ~, [; Q
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. c8 Q% s0 F, @2 ]: Y, s" k4 a
Because the pipe is horizontal, position 0 can not be placed. See figure 2
% r/ c* g" U$ Y" F( C- s6 I! lBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3/ v; x- T% v: X0 ]1 {7 Q7 s
The total heat trace that can be installed here is about
; c0 g6 X: _) x1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
+ I' t( G6 \$ P7 u& P9 ]4 cSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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" d5 H9 A2 q* R2 G, @) f2 bNote :, z9 o8 X3 c0 Q- N+ V$ w
1. The minimum bend radius:. S% Z! T7 @8 @5 s0 C7 M2 l$ e
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
. P/ }) c3 c1 M4 }/ j+ w5 {5/16 *6 = 30/16 almost = 2 inches+ c9 X* M7 Y9 @& {2 O: H
So the maximum bend radius is 2 inches.- g% K. d8 r" c3 o
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As regular 4 {% A1 ^+ T/ H7 Q+ Q7 x4 j
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe1 M: l( ^$ {' [0 ~
if the pipe is horizontal, The length of heat trace can be installed is about! U* q9 l5 P7 Y- B! z1 n
1 * 9 = 9 meters
1 J3 M" s: | o5 fIf the pipe is vertical, The length of heat trace can be installed is about9 n2 t9 f4 X0 T. H
1 * 10 = 10 meters. ' V; T ] h; {& N+ t3 f1 w: J. `
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
2 R4 c# `# d8 K3 yif the pipe is horizontal , The length of heat trace can be installed is about# b; h* D( P: f5 ~) H
1 * 4 = 4 meters
1 s) i* r+ x! B/ H1 |7 f8 XIf the pipe is vertical, The length of heat trace can be installed is about
8 ~+ U3 {9 S& {& D- _1 * 5 = 5 meters. |
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