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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置7 Q, n$ k1 ^. `8 ?; \
; |) u" C: ^/ N% ~( ^. m) J d g j& m1 ]; r$ }" b
: Z: f- i& X' p7 o" n$ P' K(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components: N9 B. G9 ~, m$ {
$ g: j5 U0 u* T5 n! s: K0 wmz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.
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Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).& j2 J3 p8 L* ~+ Q1 y2 y0 w }' Z1 q
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