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All Numbers Are Equal
/ {0 [+ O- V8 m0 R9 [. R QTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then ( \; _8 l; Z2 Y. D2 s
! R. H( K- A7 D- u2 Ca + b = t- V5 [7 Y* v3 ]$ N, @. I( r. S' A$ R
(a + b)(a - b) = t(a - b)
* |5 j b6 N3 \" t0 Ta^2 - b^2 = ta - tb# d/ q$ \5 p" Y3 o9 ]! M
a^2 - ta = b^2 - tb# J* E1 O4 {/ L3 G V, B: p5 u
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/45 O% K2 C4 ?. u% Y5 ^
(a - t/2)^2 = (b - t/2)^2
( A0 L3 p9 e6 o C4 p) r- H( da - t/2 = b - t/27 t; ~% o" E" x, i+ A" V
a = b
& H! M, K' M0 U8 e$ p1 g
' y7 K; C& U4 q; O7 nSo all numbers are the same, and math is pointless. |
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