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Suppose Intr is annually compounded
3 v a% b8 D$ G# f* m% R Month 0 Mon. 8 Mon. 12
( v5 o" G" r+ l7 A7 Y' l! K/ }Cash Principal X -750 -950 3 s% `. O+ |6 h( F% X, b* B0 b
Cash Intr (Should Pay) -X*9.5%*8/12 -(X-750)*9.5%*4/12 / K) E* s* E4 f, }" {
PV at mon 0 X -[750+X*9.5%*8/12] -[950+(X-750)*9.5%*4/12]
7 [, z. x# ]2 d0 N& Q6 b+ i6 j /(1+7.75%*8/12) /(1+7.75%*12/12)3 M# m% u9 r) E
- H( O, G6 g1 j V7 \, p- F- V" Z+ Fthese 3 should add up to 0, i.e. NPV at month 0 is 0.; w* P! L4 B; x
% Z4 f( e: k, b4 A. g O
Conclusion X = 1729.8 , j; A/ k5 [5 g8 W% q9 _. o6 V
; B3 L/ O, g# ?& [# i# l, }* [7 ~
So, Initial borrowing was 1730 *(1+7.5%) 1859.5 approx. $1,860
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