求助一到地球物理的题

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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
: U, }( N. I3 j3 j

3 ]& H) _/ d" S5 M" z
7 l' f( k/ }% d: i9 X(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
5 m5 z9 V, p% X" b5 n5 g
& a2 _5 s, U( j+ ?$ F; f8 g4 F- l( V" C2 ymz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.

, H+ M1 \7 h* f; @& [6 SCalculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).