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All Numbers Are Equal 6 M2 V* x# b3 Q6 A
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then ( `2 y( T' N- Z) D6 a' u
/ F) s2 u$ ]1 F' K: i' M# |& Va + b = t
& k4 H/ Q6 s6 U(a + b)(a - b) = t(a - b)
# ]: z, i& Q& S1 va^2 - b^2 = ta - tb
& ^( i ?' k, ?) r ma^2 - ta = b^2 - tb
3 _. G8 n' m" P( y, w$ ]a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
- P6 ?/ {- A. x" m+ f9 }(a - t/2)^2 = (b - t/2)^2
+ [( o: }* g5 `' ^: C/ t* G' R0 Ga - t/2 = b - t/2
' `/ ^ f6 _: d! ?; O4 F( T& F7 Ia = b
# n3 m; U& Q6 T' Q0 x8 X! |/ ?3 U, f2 j( G( ^/ |
So all numbers are the same, and math is pointless. |
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