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All Numbers Are Equal / Q1 _0 ]2 R4 a0 L1 n7 C& x. v" s& m; |
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
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* s+ Q. r+ }# p& L- @; X( w0 Aa + b = t
( W( K3 E' |$ @8 R% d8 o5 E(a + b)(a - b) = t(a - b). \1 b8 i5 x* Z
a^2 - b^2 = ta - tb9 N9 c" f! j' _' T( L0 Y+ ?, i
a^2 - ta = b^2 - tb
9 \$ O9 ]4 F, X2 c4 b- w% K8 o) ia^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
6 T2 S5 Y) h8 H |(a - t/2)^2 = (b - t/2)^2
3 O7 M0 o5 h- p6 d+ xa - t/2 = b - t/2/ B) N% l4 F! u+ K; k4 ?
a = b & v- R$ N& p) D. ] Q
2 h, i2 q0 ^3 H8 Q D; q) K+ pSo all numbers are the same, and math is pointless. |
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