{1 C! x# q9 }1 H0 S4 ?0 fIf #1 dead, #2 can get 50, that is the biggest number he can get. so give him 51 ( If #1 gives him only 50, what if #2 hates #1? then he can still get 50, but #1 is dead. ) 9 O, Y( c% R' M& K( L+ N7 X#5 very likly will get nothing. so give him 1 he would be happy.) R3 G2 c! m; e: o( O* g
#1 gets the rest of the 48.
Originally posted by 三思 at 2005-4-22 15:06:; U+ \4 K) H( C+ n1 \
他会提出,他和第二个第三个人平分,不给最后两个人。因为 ' l3 D7 V% z7 E* J 0 y# f; P- N- m: U" J- B他怎么分都会被后人否认(即便他自己一个不要),然后被处死,这样后面的人就可以多分。他死后,第二个第三个人面临同样的处境。 : @3 z. g& B, z, E ^ b' x2 e' V& |: P2 p/ @9 X
并且,他必须让两 ...
) G: X4 @% d& [0 oOK, If I am the #2, I would not agree that, remember, if #1 dies, #2 and #2 each get 50, then that is half agreed, right? then #2 gets 50.
Originally posted by 人生无解 at 2005-10-1 10:54: ; w; s9 x* X- U9 Z3 {1 2 3 4 5 + X' ?# P+ s1 W* a9 o48 51 0 0 1 / ]- }/ f. |8 h: Q ! n( p! M7 ?+ n" v1 V8 ^! zIf #1 dead, #2 can get 50, that is the biggest number he can get. so give him 51 ( If #1 gives him only 50, what if #2 hates #1? then he ...
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b5 V: j5 ~8 ior maybe I am wrong, what if #1 devide it to be 98 0 0 1 1??
我觉得对于一号来说最佳分配方案应该有以下3种,每一种一号都可以拿到98颗:& c# T. b$ j1 f' n2 N
(1)98-0-0-1-12 F& e- H/ B8 D& q$ `8 s$ |5 F. E; L
(2)98-0-1-0-15 u1 k- O( }1 H# y/ i; Q2 T
(3)98-0-1-1-0" t3 \3 w }9 @+ @ w