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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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足球看完了来看看题目。
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
8 T' N0 ?+ a9 AThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
: h3 w; x: g& q# g% H: _/ ~6 pWe can see it is not easy to install the 22 meters heat trace according as figure 1
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As a normal question we just discuss:4 {5 |. f& } m9 t B8 O
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 9 t( g* |! {5 _7 }( e7 C; O; ^
I call this is JACK LAI Spiral Method 螺旋法
3 `: z! ~1 p7 f& wThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
! M, ^. B# b% vThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
" T, F7 G F% y( k3 UBecause the pipe is horizontal, position 0 can not be placed. See figure 2
/ P( }" y3 [, i' P+ pBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3$ l- T" W* A! {& P& A
The total heat trace that can be installed here is about
' n" _1 V; b6 |! X1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters" d( p! T8 u) Z- R& M
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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Note :* ?! {( W( O6 Y( ~: x0 \
1. The minimum bend radius:! t5 h7 A; J4 |! y6 P
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
: M: g& @; l/ g% y5/16 *6 = 30/16 almost = 2 inches
! t( f$ y3 d i+ Q% o/ {So the maximum bend radius is 2 inches.
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Summary7 C" G7 V4 ^! \/ b7 o
As regular $ S8 u O; w. Q3 J
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
! P. T* v3 L+ L/ z0 q! k' j1 pif the pipe is horizontal, The length of heat trace can be installed is about
+ u$ w% M# X2 \! m# `0 x1 * 9 = 9 meters2 w- Z1 \' s( e# ?! Y
If the pipe is vertical, The length of heat trace can be installed is about9 ^4 x- l1 j6 P! Y4 |& e- s/ x
1 * 10 = 10 meters. 9 e' H' y, o O# o! H6 H3 ^7 \
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe. e5 E9 t1 R3 v# q1 V# `
if the pipe is horizontal , The length of heat trace can be installed is about
* g( d: r1 Q( H6 X9 e" O1 * 4 = 4 meters! t( `' \+ v/ x
If the pipe is vertical, The length of heat trace can be installed is about4 l% M! z7 o+ Q
1 * 5 = 5 meters. |
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