 鲜花( 0)  鸡蛋( 0)
|

楼主 |
发表于 2010-7-10 17:18
|
显示全部楼层
本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
' \5 x& l1 V0 `; h& q. E! l1 W/ o, X
1# jack_lai ; v3 Y+ R$ S/ a1 e+ K6 q2 H) {9 Z
- {5 |' L- X. x4 o0 A3 B/ T
足球看完了来看看题目。0 K9 A0 D- K8 q
9 h! ?, q9 ~. z" W+ @$ I- PThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)# K) l) R$ n* q( P S
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
. g5 y% A" f8 ]* V% w) BWe can see it is not easy to install the 22 meters heat trace according as figure 1& o1 Y( l2 o$ o+ U; a
, A/ x/ a; O: E3 o
5 T. U9 L/ m) Q+ u- ? B- i& K+ _
& k( i5 J% ^7 C' h) A4 f3 g% j% S. C' j) R: f6 I2 b
As a normal question we just discuss:
- i& r5 w" t( FHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
. n2 |0 ~& a# tI call this is JACK LAI Spiral Method 螺旋法
. @/ Q" E4 w6 a% G* `% N9 BThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.3 J" ?+ g4 T: X
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. 7 z3 u3 ?( }4 y" Q! ]
Because the pipe is horizontal, position 0 can not be placed. See figure 2
6 S) j2 F8 d/ x- r8 v% I% PBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
; F0 r$ K& N7 S" r! ZThe total heat trace that can be installed here is about 8 }& `! t5 d. I. @; l
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters- A+ n8 c! a7 U$ F- T+ l8 |5 x
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
4 H$ g9 Z" Z6 Z4 E( a5 [4 |( _- g" W
Note :1 v0 E; h# h& U6 E
1. The minimum bend radius:" {1 c& k* g" {$ `0 d
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
3 W9 w/ |; c) W+ f3 u1 b, e5/16 *6 = 30/16 almost = 2 inches7 `' P' h4 k% w6 d& Y
So the maximum bend radius is 2 inches.
2 V+ H1 Z& ~6 p7 S5 a: G3 M$ |) j+ _8 _3 b6 q- ?6 x8 S
( T2 w7 I+ r. d& M) I9 M G
; G( i, J P& F! u( uSummary- d: h/ g2 O" b) D ?. e
As regular
- Y6 U: A ^0 N7 R- U: YFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
: ~+ p& c5 e1 mif the pipe is horizontal, The length of heat trace can be installed is about8 y( u% n6 q( V* p6 E
1 * 9 = 9 meters
- |2 O# O) e- }- O- u+ h0 N# XIf the pipe is vertical, The length of heat trace can be installed is about- k) S" |" ?6 c0 x( S7 q0 _
1 * 10 = 10 meters.
$ \* t, N' w$ v9 DFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe( Z+ j7 Q! Z" @; E
if the pipe is horizontal , The length of heat trace can be installed is about
: U. J$ ?6 \2 n! ]1 * 4 = 4 meters
1 j- k! J+ K. V# u1 W* z. U( jIf the pipe is vertical, The length of heat trace can be installed is about
( t1 q: O6 _7 B1 * 5 = 5 meters. |
|