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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
2 w$ M1 d; F& ]6 e, x! J/ _3 K+ _5 Z% h6 K+ t# ^+ h
5 e( R# o; _& o7 R$ ~. d
7 w1 L- r6 A9 C! i. |' l9 T! j8 l(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
0 `0 `0 l, {( a# Y! e4 s$ Y
& E; b" c4 ^+ T2 z" Fmz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.7 _$ ]9 b* \: v0 `* @- Y( Y
( p* j |; T& g8 \Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).$ ?9 {3 R+ Y: A7 z' E
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