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All Numbers Are Equal
' o7 p6 W, E+ [+ gTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then * I! Q' X1 {4 w5 o. i' J
: B# m8 v7 s7 r/ Y7 za + b = t
: ?& {$ I) i: L(a + b)(a - b) = t(a - b)
5 O2 r+ }6 i" H: M0 o1 F* Aa^2 - b^2 = ta - tb8 @4 G; l5 L/ q9 ^- {! d
a^2 - ta = b^2 - tb
8 C# I K( u* Y; [1 @a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4( u% Q; j j( @6 K: W; g8 U5 _+ C
(a - t/2)^2 = (b - t/2)^2' j2 ^/ E3 F0 x, k. E3 h
a - t/2 = b - t/2# S' \- Q, ~) v) d
a = b
# m5 l( b R& v4 V2 P; m$ m4 g9 T! U0 ^
So all numbers are the same, and math is pointless. |
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