All Numbers Are Equal

我来也

All Numbers Are Equal   
; U- t8 m" k$ c3 N( ~( h# PTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
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a + b = t
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
9 ^" X9 p2 |9 Z2 V$ @+ F7 I8 k' ]& V. Ma^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
! h1 ^! C3 U7 N: i" [6 E(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
/ q/ Y9 x5 X! C: aa = b

4 G6 j7 F0 z2 |: y! R3 O9 J3 hSo all numbers are the same, and math is pointless.

老V

朋友    你算错了    在检查一遍吧

我来也

原帖由 老V 于 2006-6-13 11:05 发表
* k; k: J6 }4 b# D+ j, [朋友    你算错了    在检查一遍吧

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高桥

does a^2=b^2 implies a=b? why not a=-b?

我来也

原帖由 高桥 于 2006-6-13 12:11 发表
! t# R5 C' D0 {/ ^$ h! rdoes a^2=b^2 implies a=b? why not a=-b?

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高桥

原帖由 我来也 于 2006-6-13 21:47 发表

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