All Numbers Are Equal 0 U( O9 R7 h& O2 r! }5 jTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then 9 k; P. p( S. x) b) D # f+ h5 P: j0 K3 |) u3 Ka + b = t& N0 f- Y$ ~% P- |8 ~8 X
(a + b)(a - b) = t(a - b) 4 v" P& W" Q# I# x0 ?a^2 - b^2 = ta - tb* b, |0 X. M8 L ~
a^2 - ta = b^2 - tb+ ~1 q% I: k; j! A) W* n, V B
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4 ; x( Y. S7 ^) b/ K% J(a - t/2)^2 = (b - t/2)^2' j0 U9 a5 V- s' Z( C/ ~9 {" v: w
a - t/2 = b - t/2 - c/ t- R$ y% S/ }a = b 1 d3 Q9 O6 C* w" o. N' } 7 U2 y2 C( ?5 \# q3 qSo all numbers are the same, and math is pointless.